Question

5+3x{6-2x[2-8:(4+2xa)]}:6=7 Va rog rezolvati e cu termen necunoscut dau coroana!!!!!!!!!!!!!!

Answer 1

5+3·{6-2·[2-8:(4+2·a)]}:6=7
3·{6-2·[2-8:(4+2·a)]}:6=7-5=2
3·{6-2·[2-8:(4+2·a)]}=2·6=12
6-2·[2-8:(4+2·a)]=12:3=4
2·[2-8:(4+2·a)]=6-4=2
2-8:(4+2·a)=2:2=1
8:(4+2·a)=2-1=1
4+2·a=8·1=8
2·a=8-4=4
a=4:2=2