Question

5. a b c
si 6 a b c va rog

Answer 1

ex. 5
a ) x² + 3x + 2 = x² + 2x + x +2 = x ( x + 2 )  + ( x + 2 ) =( x + 1 ) ( x + 2 ) 
b ) x² + 5x + 4 = x² + 4x +x + 4 = x ( x + 4 ) + ( x + 4 ) = ( x +1 ) ( x + 4 ) 
c ) x² + 7x +12 = x² + 4x + 3x + 12 = x ( x + 4 ) + 3 ( x + 4 ) = ( x + 3 ) ( x + 4 ) 
ex. 6
a ) x² - 5x + 6 = x² - 2x -3 x + 6 = x  ( x - 2 ) - 3 ( x - 2  ) = ( x-3 ) ( x-2 ) 
b ) x² - 7x +12 = x² - 4x - 3x + 12 = x ( x-4 ) - 3 ( x-4 ) = ( x-3 ) ( x-4 ) 
c ) x² - 9x + 20 = x² - 4x - 5x + 20 = x ( x-4 ) -5 ( x-4 ) = ( x-5 ) ( x-4 )