Question

5) Calculati tinand cont de ordinea efectuarii operatiilor:
b) $(3*15^{2}+2*15^{12}):15^{11}+(3^{2}+3^{2})^{3}:(3^{3}+3^{3}):3+1^{2005}-2005^{0}=$

Answer 1

(3x15¹²+2x15¹²):15¹¹ +(3²+3²)³:(3³+3³):3+1²⁰⁰⁵-2005⁰=
=15¹²(3+2²):15¹¹ +(2x3²)³:(2x3³):3+1-1=
=15x7 +(2³x3⁶):(2x3²)=
=105 +2²x3⁴=
=105 +4x81=
=105+324=429