Question

5 numere inpare consecutive au suma 235 aflati numarul. folostiti doua metode! va roggg dau coroana!!❤​

Answer 1

Răspuns:

• $\blue{\bf 43~~primul ~numar ~impar}$
• $\bf\green{45~~al~doilea ~numar ~impar}$
• $\bf\orange{47~~al~treilea ~numar ~impar}$
• $\bf \purple{49~~al~patrulea ~numar ~impar}$
• $\bf \red{51~~al~cincilea ~numar ~impar}$

Explicație pas cu pas:

a = primul număr impar

a + 2 = al doilea număr impar

a + 4 = al treilea număr impar

a + 6 = al patrulea număr impar  

a + 8 = al cincilea număr impar    

$\bf a +a +2 +a +4+a+6+a+8 = 235$

$\bf 5a +20= 235$

$\bf 5a= 235 -20$

$\bf 5a= 215~~~~~\bigg|:5$

$\blue{\bf \underline{a= 43~~primul ~numar ~impar}}$

$\bf43+2 = \green{\underline{45~~al~doilea ~numar ~impar}}$

$\bf43+4 = \orange{\underline{47~~al~treilea ~numar ~impar}}$

$\bf43+6 = \purple{\underline{49~~al~patrulea ~numar ~impar}}$

$\bf43+8 = \red{\underline{51~~al~cincilea ~numar ~impar}}$

$\bf Verificare:$

$\bf 43 + 45 + 47 + 49 +51 = 235~~(adevarat)$

Answer 2

Răspuns:

a+a+2+a+4+a+6+a+8=235

5a=235-20

a=215:5

a=43

43+2=45

43+4=47

43+6=49

43+8=51

nr consecutive impare sunt:43,45,47,49,51