Question

√5 x (√2+√3)+√5(√3-√2)=
(1pe2+3pe2):4pe3=
(7pe4+5pe8-1pe16)x3pe9=
(2 pe 3 la puterea 2) x (7pe27):3pe2=
1pe15+2pe45-1pe9)x4pe3+1pe9=

Answer 1

√5 ×(√2+√3)+√5(√3-√2)=√10+√15+√15-√10=2√15
(1/2+3/2):4/3=4/2:4/3=4/2×3/4=3/2
(7/4+5/8-1/16)× 3/9=(28/16+10/16-1/16)×3/9=37/16×3/9=37/48
(2/3  la a 2a)×(7/27): 3/2=7/36
(1/15+2/45-1/9) × 4/3+1/9=(3+2-5/ totul pe 45)×4/3+1/9=1/9