Question

500-[(16×18-192:f):7+14×5+10]:4×7+9=290​

Answer 1

Răspuns:

Explicație pas cu pas:

500-[(16x18-192:f):7+14x5+10]:4x7+9=299

500-[(16x18-192:f):7+14x5+10]:4x7=290

[(288-192:f):7+14x5+10]:4x7=500-281

[(288-192:f):7+14x5+10]:4x7=210

[(288-192:f):7+70+10]=210:7x4

[(288-192:f):7+70+10]=30x4

[(288-192:f):7+70+10]=120

[(288-192:f):7=120-10-70

[(288-192:f):7=40

(288-192:f)=280

192:f=288-280

192:f=8

f=192:8

f=24