Question

500-[(16×18-192:f):7+14×5+10]:4×7+9=299​

Answer 1

Răspuns:

500-[(288-192÷f):7+70+10]:28+9=299

[(288-192:f):7+70+10]:28+9=500-299=201

[(288-192:f)÷7+70+10]:28=201-9=192

(288-192:f):7+70+10=192×28=5376

(288-192:f):7+70=5376-10=5366

(288-192:f):7=5366-70=5296

288-192:f=5296×7=42368

192:f=42368-288

192:f=42080

f=42080:193

f=219