Question

51+52+53.....+202=
va rog prin metoda suma luiGaus completa ​

Answer 1

pai afli 1+2+3+…+202 -(1+2+3+…+50) =
202x203/2-50x51/2

Answer 2

Răspuns:

Explicație pas cu pas:

• I mod

202 - 51 + 1 = 152 termeni are suma

= 152 × (51+202) : 2 =

= 152 × 253 : 2 =

= 38 456 : 2 =

= 19 228

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• al II-lea mod: adaug primele 50 de numere naturale consecutive nenule, apoi le scad

( 1+2+3+4+......+50+51+.....+202) - (1+2+3+.......+50) =

= 202 × (1+202) : 2 - 50 × (1+50) : 2 =

= 101 × 203 - 50 × 51 : 2 =

= 20 503 - 2550 : 2 =

= 20 503 - 1 275 =

= 19 228