Question

6/44
Se știe ca x supra n = y supra 3=z supra m
n,m sumt diferite de 0 si n + m = 10.Daca x= 18 si y+z=21, aflati numerele y,z,n,m
Repede va rog
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Answer 1

Explicație pas cu pas:

$\dfrac{x}{n} = \dfrac{y}{3} = \dfrac{z}{m} = \dfrac{x + y + z}{n + 3 + m} = \dfrac{18 + 21}{3 + 10} = \dfrac{39}{13} = 3$

$\dfrac{y}{3} = 3 \implies y = 9$

$y + z = 21 \iff z = 21 - 9 \implies z = 12$

$\dfrac{z}{m} = 3 \iff \dfrac{12}{m} = 3 \implies m = 4$

$n + m = 10 \iff n = 10 - 4 \implies n = 6$