Question

6. Calculați:.......

Answer 1

6a
I√3-√2I+I√3+√2I-I√2-√3I=
=(√3-√2)+(√3+√2)-(√3-√2)=
=√3-√2+√3+√2-√3+√2=
=√3+√2
6b
I1-√3I+I2-√3I-I√3-3I=
=-(1-√3)+(2-√3)-(3-√3)=
=-1+√3+2-√3-3+√3=
=-2+√3=
=√3-2
6c
I1-√2I+I2-√2I-I-2√2I=
=-(1-√2)+(2-√2)-2√2=
=-1+√2+2-√2-2√2=
=1-2√2
6d
I2-√5I+I√5-3I-I1-√5I=
=-(2-√5)+(3-√5)-(√5-1)=
=-2+√5+3-√5-√5+1=
=2-√5