Question

6.
f)x²+x-6
j)x²+4x-12
7.
b)x²-6x-7
f)x²-5x-14
j)x²-11x-26
n)x²-11x-12

Answer 1

6.
f)xpatrat + 6x - 6= xpatrat + 3x -2x -6 = x(x-2) -3(x-2)=(x-3)(x-2)
j)xpatrat + 4x -12 = xpatrat +6x-2x -12= x(x-2) + 6(x-2)=(x+6)(x-2)
7.
b)xpatrat-6x=7 => xpatrat-6x-7=xpatrat -7x + x -7= x(x+1)-7(x+1)=(x-7)(x+1)
f)xpatrat-5x-14= xpatrat-7x+2x-14= x(x+2)-7(x+2)= (x-7)(x+2)
j)xpatrat-11x-26=xpatrat -13x +2x -26 = x(x+2)-13(x+2)=(x-13)(x+2)
n)xpatrat-11x-12=xpatrat -12x +x -12 = x(x+1) -12 (x+1) = (x-12)(x+1)