Question

62gP=....moliP=....atomiP?

Answer 1

Date:

$m_P=62g$

$n_P=?$

$N_P=?$

Formule:

$n = \frac{m}{A}$

$N=n \cdot N_A$

$N_A=6,022 \cdot 10^{23} \frac{atomi}{mol}$

Rezolvare:

$n_P=\frac {m_P} {A_P} = \frac{62 \not g}{31 \frac{\not g}{mol} } = 2 \: mol$

$N_P=n_P \cdot N_A = 2 \:m ol\cdot6,022 \cdot10^{23} \frac{atomi}{mol} = 12,044 \cdot {10}^{23} atomi = 1,2044 \cdot {10}^{24} atomi$ (am simplificat mol cu mol)