Question

[(65-38):9+16:8]x3
______________=1
[21+3x(a-15:5)]:4


(ASTA E O FRACTIE!) DAU COROANA SI MULTUMESC!

Answer 1

(27:9+2)x3 supra [(21+3(a-3)]:4 = 1 =>
(3+2)x3 supra (21+3a-9):4=1 =>
5x3 supra (12+3a):4=1 =>
15x4 supra (12+3a)=1 => 60=12+3a => 3a=48=> a=16

Answer 2

[(65-38)÷9+16÷8]×3supra[21+3×(a-15÷5)]÷4=1
[(27)÷9+2]×3supra(21+3a-9)÷4=1
(3+2)×3supra(21+3a-9)÷4=1
15/(12+3a)÷4=1
15×4/(12+3a)=1
60/=12+3a
3a=60-12
3a=48
a=48÷3
a=16