Question

(6radical din 3)² - (2 radical din 3)²

Answer 1

(6√3)² - (2√3)²= 36*3 - 4*3 = 3(36-4) = 3* 32= 96

Answer 2

Folosim formula $a^{2}$-$b^{2}$=(a+b)(a-b)
unde a=6 radical din 3
         b=2radical din 3
=> (6$\sqrt{3}$+2$\sqrt{3}$)(6$\sqrt{3}$-2$\sqrt{3}$)=(8$\sqrt{3}$)* (4[tex] \sqrt{3 } [/tex])=32*3=96