Question

7 / 3 ori 2^97 = 3n -1 / 4^50 -2^98 
n=?

Answer 1

$\frac{7}{3* 2^{97} } = \frac{3n + 1}{ 4^{50}} - 2^{98}$

$\frac{7}{3* 2^{97}} = \frac{3n+1}{ 2^{100}} - \frac{ 2^{98} }{1}$

Aducem la acelasi numitor:

$\frac{ 2^{3} * 7}{3 * 2^{100}} = \frac{3(3n+1)}{3* 2^{100}} - \frac{3* 2^{100}* 2^{98}}{3* 2^{100}}$

$2^{3} * 7 = 3(3n + 1) - 3* 2^{100} * 2^{98}$

$56 = 9n + 3 - 3* 2^{198}$

$9n = 3* 2^{198} + 56 - 3$

$n = \frac{3* 2^{198} + 53}{9}$