Question

-7(3radical din 2+radical din 3)+3(radical din8+radical din 12).

Answer 1

• -7(3√2+√3)+3(√8+√12)=
• =-21√2-7√3+3(2√2+2√3)
• =-21√2-7√3+6√2+6√3
• =-15√2-√3

Answer 2

-7 (3 radical 2 + radical 3) + 3(radical 8 + radical 12) = -21 radical 2 - 7 radical 3 + 3 radical 2 + 6 radical 3 =  - 18 radical 2 - radical 3