Question

7 ( pe c si d le-am facut eu ) si pe 8 va rog ,

Answer 1

$a) (3-2 \sqrt{2} )( \sqrt{17+12 \sqrt{2} }) + (\sqrt{7+4 \sqrt{3} }) ( \sqrt{3} -2) \\ (3-2 \sqrt{2} )( \sqrt{(3+2 \sqrt{2} ) ^{2} }~) +( \sqrt{( \sqrt{3} +2) ^{2} } )(\sqrt{3} -2) \\ (3-2 \sqrt{2} )(3+2 \sqrt{2} )+( \sqrt{3}+2)( \sqrt{3} -2) \\ 3 ^{2} -(2 \sqrt{2} ) ^{2} +( \sqrt{3} ) ^{2} -4 \\ 9-8+3-4 \\ Raspunsul~=0 \\ Punctul~b) \\ \sqrt{3} + \sqrt{6} ( \frac{1}{ \sqrt{3} } + \frac{1}{ \sqrt{2} } )- 4\sqrt{6} ( \frac{1}{ \sqrt{8} }- \frac{1}{ \sqrt{12} } )-3 \sqrt{2} \\  \sqrt{3} + \frac{ \sqrt{6} }{ \sqrt{3} } + \frac{ \sqrt{6} }{ \sqrt{2} } - \frac{4 \sqrt{6} }{ \sqrt{8} } + \frac{4 \sqrt{6} }{ \sqrt{12} } -3 \sqrt{2} \\ \sqrt{3}+ \sqrt{2} + \sqrt{3} -2 \sqrt{3} +2 \sqrt{2} -3 \sqrt{2} \\ 2 \sqrt{3} -2 \sqrt{3} +3 \sqrt{2} -3 \sqrt{2} \\ Raspuncul~=0$