Question

700 mg C6H(benzen) de puritate 70% se supune arderii.Se cere volumul de aer si ms Ca(OH)2 c=40%.

Answer 1

Calculam masa de benzen pura
p/100=mpura/mimpura
70/100=mpura/700 => mpura=700*70/100=490mg=0,49g benzen
78g.......7,5*22,4l..6moli
C6H6 + 7,5O2 -> 6CO2 + 3H2O
0,49g....x=?.........y=?
x=0,49*7,5*22,4/78=1,055l O2
y=0,49*6/78=0,0377moli CO2
Vaer=5VO2=5*1,055=5,275l aer
74g............1mol
Ca(OH)2 + CO2 -> CaCO3 + H2O
z=?............0,0377moli
z=0,0377*74=27,898≈27,9g Ca(OH)2
c/100=md/ms => ms=md*100/c=27,9*100/40=69,75g solutie Ca(OH)2