Question

[72 :(48-x)+58]:10=147

Answer 1

$[72:(48-x)+58]:10=147 \\ 72:(48-x)+58=147*10 \\ 72:(48-x)+58=1470 \\ 72:(48-x)=1470-58 \\ 72:(48-x)=1412 \\ 48-x= \frac{72}{1412} \\x=47 \frac{335}{353}$

Answer 2

72 : (48 - x) + 58 = 147 * 10
72 : (48 - x) = 1470 - 58
72 = 1412(48 - x)
72 = 67 776 - 1412x
1412x = 67 776 - 72
1412x = 67 704
x = 67 704 : 1412
x = 47 si 1340/1412
x = 47 si 335/353