Question

776,34 mL solutie de hidroxid de potasiu 10% si densitate 1,082g/mL reactioneaza cu o solutie de acid sulfuric de concentratie 20% si densitate de 1,143g/mL. Calculeaza volumul solutiei de acid folosita si masa de apa din final?

VAA ROGGG .CHIAR AM NEVOIE DE REZOLVARE LA PROBLEMA ASTA.OFER 15 puncte. URGENT VA ROG !!

Answer 1

ro=ms/Vs=>ms=ro*Vs=1,082*776,34=840g sol KOH

C=md/ms*100=>md=C*ms/100=10*840/100=84g KOH

n=m/M=84/56=1,5 moli KOH

ms=md+mH2O=>mH2O=ms-md=840-84=756g

2 moli......98g..............................2*18g
2KOH + H2SO4 => K2SO4 + 2H2O
1,5 moli....x=73,5g......................y=27g

C=md/ms*100=>ms=md*100/C=73,5*100/20=367,5g sol H2SO4

ms=md+mH2O=>mH2O=ms-md=367,5-73,5=294g

ro=ms/Vs=>Vs=ms/ro=367,5/1,143=321,522 mL sol H2SO4

mH2O final = 756+294+27=1077g