Question

8^33/[4^32*2^34+(2^5*2^20)^5/(16*2^23)+(75/75-2^0)*32*4=

Answer 1

=2^3^33:[2^2^32*2^34-2^25^5]:(2^4*2^23)+(1-1)*128=
2^99:[2^64*2^34-2^125:2^27]+0*128=
2^99:[2^98-2^98]+0=2^99:0=0