Question

(8 la 37 × 81 la 25)÷(16 la 27 × 27 la 33 )

Answer 1

(8^37x81^25):(16^27x27^33)=24
cu rezolvare
8^37=(2^3)^37=2^111
81^25=(3^4)^25=3^100
16^27=(2^4)^27=2^108
27^33=(3^3)^33=3^99
la impartirea puterilor cu aceasi baza exponentii se scad.
2^3x3=8x3=24⇒rezultat final

Answer 2

$[( 2^{3}) ^{37} *( 3^{4}) ^{25} ]:[( 2^{4} )^{27} *( 3^{3}) ^{33} ]$

$(2^{111} * 3^{100} ):( 2^{108} * 3^{99} )$

$2^{111-108} * 3^{100-99}$

$2^{3} *3$

8*3=24