Question

(8 la puterea 4 :4la puterea 5 +27 la puterea 9 :3 la puterea 24+2 la puterea 12:2 la puterea 11): 3

Answer 1

(8^4 : 4^5 + 27^9 : 3^24+2^12:2^11) : 3 =

= [(2^3)^4 : (2^2)^5 +(3^3)^9:3^24+2^1]:3=

= ( 2^12 : 2^10 + 3^27 : 3^24 + 2) : 3 =

= (2^2 + 3^3 + 2) : 3 =

= (4 + 27 +2) : 3 =

= 33 : 3 =

= 11