Question

(8 la puterea 8 -8 la 12:2 la 24)totul la 2:(2 la 24-4 la 12 :8 la 8):(16la6-64)totu la 0=
ajutati-ma pls!!!!

Answer 1

 = $[(2^{3})^{8}- (2^{3})^{12} : 2^{24}]^{2} : [( 2^{24} - (2^{2})^{12}: (2^{3})^{8}] :1$ 
 = $(2^{24} - 2^{36}: 2^{24})^{2} : ( 2^{24} - 2^{24}:2^{24})$
 = $(2^{24}-2^{12})^{2} : ( 2^{24} - 1) = [2^{12}(2^{12}-1)]^{2} : ( 2^{24}-1) = 2^{24}(2^{12}-1)^{2}:$ $(2^{24} -1 )$ = $2^{24}(2^{12}-1)^{2} : (2^{12}-1)(2^{12}+1) =   = 2^{24}(2^{12}-1) : (2^{12} + 1)$ ... mai multe nu pot face ...