Question

(814-810)xd;[(8+8;8x32)-30]-28=50
te rog......!

Answer 1

(814-810)xd=
=4xd=
=4d

{(8+8:8x32)-30}-28=50
{(8+32)-30}-28=50
{40-30}-28=50
10-28=50 / +28
10=50+28
10=78

Answer 2

[(814-810)*d]:[(8+8:8*32)-30]-28=50
4d:[(8+32)-30]-28=50
4d:(40-30)-28=50
4d:10-28=50
4d:10=28+50
4d:10=78
4d=78*10
4d=780
d=780:4
d=196

Si alta metoda

2d:5-28=50
Numitorul comun 5
Avem:
2d:5-140:5=50
(2d-140):5=50
Inmultim ambele parti cu 5
[5(2d-140)]:5=50*5
2d-140=5*50
2d-140=250
2d=140+250
2d=390
d=390:2
d=195