Matematică, întrebare adresată de teodorateo639, 9 ani în urmă

82 puncte daca le faceti pe toate ;) 
Rezolvati:
a) (x+192:2) * (ori) 3 + 59 * 4 = 1988
b) 4x-23=43+3x+3-21 * 2 
c) 5* [2* (3x+2) - 11 ] +2+4=27+4
d) 10 * { x - 10 * [362+10 * (24+24:4)]}=100
e) {2 * [20 - (5+x) : 6] -5} : 9 + 17 = 20

Calculati: 
a) 1 supra 2 + 3 supra 4
b) 5 supra 3 ori 4 supra noua + 2 supra 3 : 8 supra 12
c) 1 supra 2 la puterea 2 + 2 supra 2 la puterea 3 - 1 supra 2 la puterea 2
d) 1 supra 2 + 3 supra 4 * ( 5 supra 6 - 3 supra 4 * 4 supra 3 - 10 supra 12)
e) [( 35 supra 75 + 2 supra 6 - 2 supra 10) * 5 supra 4 + (2 supra 4 - 2 supra 8) : 5 supra 12] * 2 supra 7
c) 2 intregi 4 supra 5 * ( 2 intregi 14 supra 20 * 20 supra 63 - 28 supra 30 : 1 intreg 3 supra 25) 

FACETI-LE PE TOATE ;;) 

Răspunsuri la întrebare

Răspuns de OctavianTeodor
27
a)(x+96)*3+236=1988=1988-236=1752
x+96=1752:3=584⇒x=584-96=488;x=488
b)4x-23=46-42+3x⇒x=23+4=27
c)5*[2*(3x+2)-11]=31-6=25
2*(3x+2)-11=25:5=5
(3x+2)=5+11=16
3x+2=16:2=8
3x+28⇒3x=6⇒x=6:3=2
d)x-10*[362+10*(24+6)]=100:10=10
x-10*(362+10*30)=10
x=10+6620
x=6630
e){2*[20-(5+x):6]-5}:9=20-17=3
2*[20-(5+x):6]-5=3*9=27
2*[20-(5+x):6=27+5=32
20-(5+x):6=32:2=16
(5+x):6=20-16=4
5+x=6*4=24
x=24-5
x=19
2)a) \frac{1}{2} + \frac{3}{4} = \frac{5}{4}=1 \frac{1}{4}

b) \frac{5}{3}* \frac{4}{9} + \frac{2}{3}: \frac{8}{12} = \frac{20}{27}+ \frac{2}{3}* \frac{12}{8}=<br />\frac{20}{27}+ \frac{24}{24}=1 \frac{20}{27}

c)(\frac{1}{2})^{2} +(\frac{2}{2})^{3}-(\frac{1}{2})^{2}=1
d)enuntul este gresit!
[tex] (\frac{14+10-6}{30}* \frac{5}{4}+ \frac{2}{8} * \frac{12}{5})* \frac{2}{7}= ( \frac{18}{30}*
\frac{5}{4}+ \frac{24}{40})* \frac{2}{7}=( \frac{90}{120}+ \frac{24}{40})* \frac{2}{7}=[/tex]

(\frac{3}{4}+ \frac{3}{5})* \frac{2}{7}= \frac{15+12}{20}* \frac{2}{7}= \frac{27}{20}* <br />\frac{2}{7}=[tex] \frac{54}{140}= \frac{27}{70}
e) \frac{14}{5}*( \frac{54}{20}* \frac{20}{63}- \frac{28}{30}* \frac{25}{28})= \frac{14}{5}* <br />(\frac{6}{7}- \frac{5}{6})= \frac{14}{5}* \frac{1}{42}= \frac{1}{15}

Răspuns de Miky93
17
a)(x+96)*3+236=1988
(x+96)*3=1988-236=1752

x+96=1752:3
x+96=584
x=584-96
x=488

b)4x-23=43+3x+3-42
4x-23=1+3+3x
4x-23=4+3x
4x-3x=4+23
x=27

c)5* [2* (3x+2)-11]+6=31
5* [2*(3x+2)-11]=31-6=25

2*(3x+2)-11=25:5=5

2*(3x+2)=5+11=16

3x+2=16:2
3x+2=8
3x=8-2=6
3x=6
x=2

d)x-10*[362+10*(24+6)]=100:10=10
x-10*(362+10*30)=10

x-(362+300)=10:10=1

x-662=1
x=1+662
x=663

e){2*[20-(5+x):6]-5}:9=20-17=3
2*[20-(5+x):6]-5=3*9=27

2*[20-(5+x):6]=27+5=32

20-(5+x):6=32:2=16

-(5+x):6=16-20

-(5+x):6=-4

5+x=4*6
5+x=24
x=24-5
x=19

2)a)1/2+3/4= (2+3)/4= 5/4=1,2

b)5/3 *4/9+2/3 :8/12= 20/27 + 2/3 * 12/8= 20/27 + 1= (20+27)/27= 57/27=2,11

c) (1/2)²+ (2/2)³ - (1/2)²= (2/2)³= 8/8=1

d)1/2 + 3/4 * (5/6-3/4 * 4/3 -10/12)= 1/2 + 3/4 *( 5/6 -1 -5/6)= 1/2 + 3/4 *(-1)=

=1/2 -3/4= (2-3)/4= -1/4= -0,25

e)[(7/15 +1/3-1/5)*5/4 + (1/2 -1/4): 5/12] *2/7= [(7+5-3)/15 * 5/4 + (2-1)/4 * 12/5] *2/7=

= ( 9/15 *5/4 + 1/4 *12/5 ) *2/7= ( 3/4 + 3/5) * 2/7= (15+12)/20 *2/7= 27/20 * 2/7=  27/70= =0,385

f)2 intregi 4/5= 14/5
2 intregi 14/20= 54/20= 27/10
1 intreg 3/25= 28/25

14/5 : ( 27/10 * 20/63  -28/30 :28/25)= 14/5 * ( 6/7 - 28/30 *25/28)=

=14/5 : (6/7 * 5/6)= 14/5 : 7/5=  14/5 * 5/7= 2

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