Question

9×{8+7×[6+5×(4+3×(2+1))]}:(1+2+3+...+9)​

Answer 1

Răspuns:

972

Explicație pas cu pas:

9x{8+7x[6+5x(4+3x(2+1))]} : (1+2+3+...+9)=

9x[8+7x(6+5x(12x3))] : (1+2+3+...+9)=

9x[8+7x(11x36)] : (1+2+3+...+9)=

9x(8+7x396)] : (1+2+3+...+9)=

9x(15x396) : (1+2+3+...+9)=

9x5940 : 55=

9x108=

=972

Explicatia ecuatiei (1+2+3+...+9)

S=1+2+3+...+(n-1)+n=nx(n+1):2

1+2+3+...+9+10=10x(10+1):2

S=10x11:2

S=110:2

S=55