Question

9(intregi)3supra4+3(intregi)1supra6

Answer 1

$9 \frac{3}{4} +3 \frac{1}{6} = \frac{39}{4} + \frac{19}{6} aducem.la.acelasi.numitor.comun \\ \\ \frac{117}{12} + \frac{38}{12} = \frac{155}{12} =12,916$

Answer 2

(9*4+3) /4+ (3*6+3)/6= 39/ 4 + 19 / 6= 117 /12 +38/ 12 = 155 /12