Question

9 la puterea 19 ori 27 totul in paratenza la putere 2 impartit la 3la puterea 5

Answer 1

${ {(9}^{19} \times 27)}^{2} \div {3}^{5}$

$={[ { {(3}^{2} )}^{19} \times {3}^{3}]}^{2} \div {3}^{5}$

$={( {3}^{2 \times 19} \times {3}^{3} )}^{2}\div {3}^{5}$

$={( {3}^{38} \times {3}^{3}) }^{2}\div {3}^{5}$

$={( {3}^{38 + 3 })}^{2} \div{3}^{5}$

$= {({3}^{41})}^{2} \div{3}^{5}$

$= {3}^{41\times2}\div{3}^{5}$

$={3}^{82}\div{3}^{5}$

$={3}^{82-5}$

$={3}^{77}$