Question

9 la puterea 45 impartit la 3 si 27 la puterea 29 este divizibil cu 10​

Answer 1

${9}^{45} \div {3}^{27} = ( {3}^{2} ) {}^{45} \div 3 {}^{27} = {3}^{90} \div {3}^{27} = {3}^{63}$

${27}^{29} = ( {3}^{3} ) {}^{29} = {3}^{87}$