Question

9a patrat +16bpatrat mai mic sau egal ca 24ab a,b apartine r cu stea
b/a=

Answer 1

[tex]9 a^{2} +16b \leq 24ab [/tex]

$9 a^{2} -24ab+ 16 b^{2} \leq 0$
$(3a- 4b) ^{2} \leq 0$

3a ≤ 4b
a/b ≤ 4/3
b/a≤ 3/4