Question

a) 1 pe 2 + 1 pe 2 + 1 pe 6
b) 2 pe 5 + 3 pe 2 + 7 pe 10
c) 4 pe 9 + 1 pe 3 + 7 pe 18
d) 1 pe 40 + 3 pe 8 + 7 pe 4 + 1 pe 2

OFER CORONIȚĂ !

Answer 1

$\dfrac{1}{2}^{ \times 6} + \dfrac{1}{2}^{ \times 6} + \dfrac{1}{6}^{ \times 2} = \dfrac{6}{12} + \dfrac{6}{12} + \dfrac{2}{12} = \dfrac{14}{12} ^{ \div 2} = \dfrac{7}{6}$



$\dfrac{2}{5} ^{ \times 2} + \dfrac{3}{2}^{ \times 5} + \dfrac{7}{10} = \dfrac{4}{10} + \dfrac{15}{10} + \dfrac{7}{10} = \dfrac{26}{10} ^{ \div 2} = \dfrac{13}{5}$




$\dfrac{4}{9} ^{ \times 2} + \dfrac{1}{3} ^{ \times 6} + \dfrac{7}{18} = \dfrac{8}{18} + \dfrac{6}{18} + \dfrac{7}{18} = \dfrac{21}{18}^{ \div 3} = \dfrac{7}{6}$



$\dfrac{1}{40} + \dfrac{3}{8}^{ \times 5} + \dfrac{7}{4}^{ \times 10} + \dfrac{1}{2}^{ \times 20} = \dfrac{1}{40} + \dfrac{15}{40} + \dfrac{70}{40} + \dfrac{20}{40} = \dfrac{106}{40}^{ \div 2} = \dfrac{53}{20}$