Question

a=√10+√3+√2
b=√10-√3-√2
Calculati media aritmetica si media geometrica.

Answer 1

a=3,16+1,73+1,41=4,89+1,41=6,3
b=3,16-1,73-1,41=1,43-1,41=0,02
Media aritmetica= $\frac{a+b}{2}$ = $\frac{6,3+0,02}{2}$ = $\frac{6,32}{2}$ = 3,16

Media geometrica=$\sqrt{a*b}$ = $\sqrt{6,3*0,02}$ =$\sqrt{0,126}$

Answer 2

ma=a+b/2=√10+√3+√2 +√10-√3-√2  /2 =2√10 /2=√10

mg=√a*b

a*b=(√10+√3+√2)*(√10-√3-√2)=10 - (3+2+2√6)= 5 -2√6=(√3-√2) la  2
deci mg=√a*b=√(√3-√2) la  2 =√3-√2