Question

a)100:(3^4+3+3^4-11)+2017
b)4^3:8^2+25^4:125^2+2+2^15:(2^5)^3-0^7+7^0+7^1-1^7
c) (10+2^10×3^10):(6^10+10)

Answer 1

Corectie: 100 ; ( 3³ NU 3⁴ .. )

a)  100 : ( 3³+3 + 3⁴ - 11  ) + 2017 =  2018

=  100 : ( 27 + 3 + 81 - 11 ) + 2017 =

= 100 : ( 111 - 11 ) + 2017 =

= 100 : 100 + 2017 =

= 1 + 2017 =

= 2018

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b)

4⁴ : 8² + 25⁴ : 125² + 2 x 2¹⁵ : ( 2⁵ )³ - 0⁷ + 7⁰ + 7¹ - 1⁷ = 38

= ( 2² )⁴ : ( 2³ )² + ( 5² )⁴ : ( 5³ )² + 2⁽ ¹⁺¹⁵ ⁾ : 2⁵ˣ³ - 0 + 1 + 7 - 1 =

= 2²ˣ⁴ : 2³ˣ² + 5²ˣ⁴ : 5³ˣ² + 2¹⁶ : 2¹⁵ + 7 =

= 2 ⁽ ⁸ ⁻ ⁶ ⁾  + 5 ⁽ ⁸ ⁻ ⁶ ⁾ + 2 ⁽ ¹⁶ ⁻ ¹⁵ ⁾ + 7 =

= 2² + 5² + 2 + 7 =

= 4 + 25 + 9 =

= 38

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c)

( 10 + 2¹⁰ x 3¹⁰ ) : ( 6¹⁰ + 10 ) = 1

= [ 10 + ( 2 x 3 )¹⁰ ] : ( 10 + 6¹⁰ ) =

= ( 10 + 6¹⁰ ) : ( 10 + 6¹⁰ ) =

= 1