Question

a. 1²⁰²⁰-2020⁰+3²-2³= b. 2¹²:2¹⁰+5²-3²+2018⁰= c.2019⁰+1²⁰¹⁹+2018¹+0²⁰¹⁸-2017¹= d.[(2³+2⁴+2⁵+2⁶)+(2²+2³)]×(1+3+3²+3³)
Va rog! dau coroana ​

Answer 1

Explicație pas cu pas:

a. 1²⁰²⁰-2020⁰+3²-2³=

= 1 - 1 + 9 - 8 =

= 0 +1

= 1

b. 2¹²:2¹⁰+5²-3²+2018⁰=

= 2^2 + 25 - 9 + 1

= 2 + 25 - 9 + 1

= 27 - 9 +1

= 18 + 1

= 19

c.2019⁰+1²⁰¹⁹+2018¹+0²⁰¹⁸-2017¹=

= 1 +1 + 2018 + 0 - 2017

= 2 + 2018 - 2017

= 2 + 1

= 3

d.[(2³+2⁴+2⁵+2⁶)+(2²+2³)]×(1+3+3²+3³) =

= [( 8 + 16 + 32 + 64) + (4+8)] × ( 4 + 9 + 27)

= [ ( 40 + 80) + 12] × ( 13 + 27)

= (120 + 12) × 40

= 132 × 40

= 5280

Answer 2

Explicație pas cu pas:

ღSalutare!ღ

a) 1²⁰²⁰-2020⁰+3²-2³=1-1+9-8=0+9-8=9-8=1

b) 2¹²:2¹⁰+5²-3²+2018⁰=2^(12-10)+25-9+1=2²+25-9+1=4+25-9+1=29-9+1=20+1=21

c) 2019⁰+1²⁰¹⁹+2018¹+0²⁰¹⁸-2017¹=1+1+2018+0-2017=2+2018+0-2017=2020+0-2017=2020-2017=3

d) [(2³+2⁴+2⁵+2⁶)+(2²+2³)]×(1+3+3²+3³) = [(8+16+32+64)+(4+8)]×(4+9+27) = [(24+32+64)+12]×(13+27) = [(56+64)+12]×50=(120+12)×40=132×40=5280

^ = la puterea

Succes!;)