Question

{[(a+2)×2+2]×2+2}×2+2=30 Vă rog ajutațimă!!!!! Repede!

Answer 1

{ [ ( a + 2 ) × 2 + 2 ] × 2 + 2 } × 2 + 2 = 30

{ [ ( a + 2 ) × 2 + 2 ] × 2 + 2 } × 2 = 30 - 2

{ [ ( a + 2 ) × 2 + 2 ] × 2 + 2 } × 2 = 28

[ ( a + 2 ) × 2 + 2 ] × 2 + 2 = 28 : 2

[ ( a + 2 ) × 2 + 2 ] × 2 + 2 = 14

[ ( a + 2 ) × 2 + 2 ] × 2 = 14 - 2

[ ( a + 2 ) × 2 + 2 ] × 2 = 12

( a + 2 ) × 2 + 2 = 12 : 2

( a + 2 ) × 2 + 2 = 6

( a + 2 ) × 2 = 6 - 2

a + 2 = 4 : 2

a + 2 = 2

a = 2 - 2

a = 0 → numarul, aflat prin metoda mersului invers

Answer 2

{[(a+2)x2+2]x2+2}x2+2=30
{[(a+2)x2+2]x2+2}x2=30-2
{[(a+2)x2+2]x2+2}x2=28
[(a+2)x2+2]x2+2=28:2
[(a+2)x2+2]x2+2=14
[(a+2)x2+2]x2=14-2
[(a+2)x2+2]x2=12
(a+2)x2+2=12:2
(a+2)x2+2=6
(a+2)x2=6-2
(a+2)x2=4
a+2=4:2
a+2=2
a=2-2
a=0


Sper să fie bine!