Question

(a:2) + (a:4)=141 
si inca unul..
(ax2)+(a:2)=505

Answer 1

     
$(a:2) + (a:4)=141 \\ \\ \frac{a}{2} + \frac{a}{4}=141 \\ \\ \frac{2a}{4} + \frac{a}{4}=141 \\ \\ \frac{2a+a}{4} =141 \\ \\\frac{3a}{4} =141 \\ \\ 3a=141*4 \\ a= \frac{141*4}{3} =47*4=188$
   
     
$(ax2)+(a:2)=505 \\ 2a+ \frac{a}{2}=505 \\ \frac{4a}{2}+ \frac{a}{2}=505 \\ \frac{4a+a}{2}=505 \\ \frac{5a}{2}=505 \\ 5a=505*2 \\ a= \frac{505*2}{5}=101*2=202$