Question

a+2b+3c=43 ,a:b=2 rest6 , b: c= 2 rest1

Answer 1

a:b=2 +6
a=2b+6
b:c=2+1
b=2c+1
a=2*(2c+1)+6=4c+2+6=4c+8
a+2b+3c=4c+8+2(2c+1)+3c=4c+8+4c+2+3c=11c+10
11c+10=43, scadem 10
11c=33, impartim la 11
c=3
b=2c+1=6+1=7
a=2b+6=2*7+6=14+6=20

Answer 2

a : b = 2 rest 6
a = 2b + 6
b : c = 2 rest 1
b = 2c + 1
a = 2(2c + 1) + 6
a = 4c + 8
inlocuim pe a a si pe b
a + 2b + 3c = 43
4c + 8 + 2(2c + 1) + 3c = 43
4c + 8 + 4c + 2 + 3c = 43
11c = 33
c = 33 : 11
c = 3
a = 4 * 3 + 8
a = 20
b = 2 * 3 + 1
b = 7