Question

a= 3^2011- 3^2010 -3^2009-3^2008
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Answer 1

$a = {3}^{2011} - {3}^{2010} - {3}^{2009} - {3}^{2008}$

$a = ( {3}^{3} - {3}^{2} - 3 - 1) \times {3}^{2008}$

$a = (27 - 9 - 3 - 1) \times {3}^{2008}$

$a = 14 \times {3}^{2008}$

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