Question

a)3-√3supra lui 3√2-√6 va roggggggggggggggg

Answer 1

ii foarte usor introduci factorii sub radical shi efectuezi scaderea shi vualea

Answer 2

$\displaystyle \frac{3- \sqrt{3} }{3 \sqrt{2} - \sqrt{6} } = \frac{(3- \sqrt{3} )(3 \sqrt{2} + \sqrt{6} )}{18-6} = \frac{9 \sqrt{2} +3 \sqrt{6}-3 \sqrt{6} - \sqrt{18} }{12} = \\ \\ = \frac{9 \sqrt{2} -3 \sqrt{2} }{12} = \frac{6 \sqrt{2} }{12} = \frac{ \sqrt{2} }{2}$