Question

a) 3x² - 6x = 0;
b) 6x² – 5x = 0;
c) –4x² + 24x = 0;
d) (x - 1)² = 0;
e) 36x² – 25 = 0;
f) 2x² – 18 = 0;
vă rog si o explicație ​

Answer 1

a) 3x^2-6x=0=>3x^2=6x/3x=>x=2
b) 6x^2-5x=0=>6x^2=5x/x=>6x=5=>x=5/6
c) -4x^2+24x=0=>-4x^2=-24x/(-4x)=>x=6
d)(x-1)^2=0=>x^2-2x+1=0=> Delta=b^2-4ac=(-2)^2-4*1*1=0=> are o singura soluție =>x=-b/2a=2/2=1
Deci x=1
e) 36x^2-25=0=>36x^2=25=>x^2=25/36=>x=5/6
f) 2x^2-18=0=>2x^2=18=>x^2=9=>x=3