Question

a) ( 4-2x) √ 3 + ( y+2) * √2=0
b) daca  x ² - y ² =48si y-x=6, calculati 3(x+y)

Answer 1

a)
[tex](4-2x)\sqrt{3}+(y+2)\sqrt{2}=0\sqrt{3}+0\sqrt{2}=>\\ \left \{ {{4-2x=0=>x=2} \atop {y+2=0=>y=-2}} \right. [/tex]
b)
[tex]x^2-y^2=48|\cdot(-1)\\ y^2-x^2=-48\\ (y-x)(y+x)=-48\\ 6(y+x)=-48\\ y+x=-48:6=-8\\ x+y=-8\\ 3(x+y)=3\cdot(-8)=-24[/tex]