Question

a=4 supra radical din 3 -1 ; b= 4-radical din 6 × radical din 2 ;aflati media aritmetica a celor doua numere

Answer 1

a=4/√3-1=4(√3+1)/(√3-1)(√3+1)=4√3+4/2;
b=4-√6*√2=4-2√3;
Ma=a+b/2;
Ma=(4√3+4/2+4-2√3)/2=(2(2√3+2)/2+4-2√3)/2=(2√3+2+4-2√3)/2=
=6/2=3;
Raspuns:Ma=3.
Bafta!