Question

a=[(5/2)la puterea 3]la puterea2:(25/4)la putere3-2,(3)×9/7 si b=(5/28:2/7-1/8)[3,(6)-7/3]+[(-5/2)la puterea3]la puterea7:[(-5/2)la puterea4]la putetea5​

Answer 1

Răspuns:

A=[(5/2)la puterea 3]la puterea2:(25/4)la putere3-2,(3)×9/7

A=[(5/2)^3]^2: (25/4)^3- (23-2)/9×9/7

A=[(5/2)^6]: [(5/2)^2]^3- 21/9×9/7

A=(5/2)^6 : (5/2)^6-3

A=1 - 3

A= - 2

b=(5/28:2/7-1/8)[3,(6)-7/3]+[(-5/2)la puterea3]la puterea7:[(-5/2)la puterea4]la putetea5​

b=(5/28×7/2-1/8)[(36-3)/9-7/3]+

[(-5/2)^3]^7:[(-5/2)^4]^5

b=(5/8-1/8)[(33/9-7/3)]+(-5/2)^21:

(-5/2)^20

b=4/8(11/3-7/3)+(-5/2)^1

b= 1/2(4/3)+(-5/2)

b= 4/6-5/2

b= 4/6-(5×3)/6

b=(4-15)/6

b= - 11/6

Explicație pas cu pas: