Question

a) 99099:x=99; c) 129+47334:x=2187; e) 73-15+40032:x=1512; g) (102:x-47:x):5=11; i) (288:x-8):4-5=1; (342:x-6):2-375:75=1; b) d) 312: (x+6)=26; f) 1490-1490:x=745; h) (49:x+51:x):5=4; j) [(25:x+20:x): 3] +5=8.​

Answer 1

Ecuatiile

cu

necunoscuta

- se "izoleaza" necunoscuta prin operatii inverse/

metoda mersului invers

a) 99099:x=99

x=99099:99

x=1001

c) 129+47334:x=2187

47334:x=2058

x=47334:2058

x=23

d) 312: (x+6)=26

x+6=312:26

x+6=12

x=6

e) 73-15+40032:x=1512

58+40032:x=1512

40032:x=1512-58

40032:x=1454

x=40032:1454

x=27,53

f) 1490-1490:x=745

1490:x=1490-745

1490:x=745

x=1490:745

x=2

g) (102:x-47:x):5=11

102:x-47:x=55

(102-47):x=55

x=55:55

x=1

h) (49:x+51:x):5=4

(49+51):x=20

100:x=20

x=5

i) (288:x-8):4-5=1

288:x-8=6×4

288:x=32

x=288:32

x=9

j) [(25:x+20:x): 3] +5=8

(25+20):x=3×3

45:x=9

x=5

Un alt exercitiu gasesti aici: https://brainly.ro/tema/9908346

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