Question

a/b=0.(3) aflati valoarea raportului 17a-2b/2a+3b. as dori poza cu rezolvarea. Stiu ca era o regulă dar am.uitat-o.

Answer 1

$\frac{a}{b} = 0.(3) = \frac{3}{9} = \frac{1}{3}$
=> a=1 si b=3
$\frac{17a - 2b}{2a + 3b} = \frac{17 \times 1 - 2 \times 3}{2 \times 1 + 3 \times 3} = \frac{17 - 6}{2 + 9} = \frac{11}{11} = 1$

Answer 2

$\frac{a}{b}=0,(3)=\frac{3}{9}=\frac{1}{3}\\\\ b=3a\\ \\ \frac{17a-2b}{2a+3b}=\frac{17a-2\cdot3a}{2a+3\cdot3a} =\frac{17a-6a}{2a+9a} =\frac{11a}{11a} =1$