Question

a+b=1125 si a:b=9 rest 5 afla a si b

Answer 1

A+b=1125 a:b=9 rest 5 conform teoremei impartirii cu rest:  a=9b+5
a+b=1125  si a=9b+5

9b+5+b=1125
10b=1125-5
b=1120:10
b=112
a=9b+5=9×112+5=1013
a=1013  si b=112
Verificare:
A+b=1125      ⇒    1013+112=1125⇒1125=1125