Question

a+b =3√6 stiind ca ab =16 calculeaza a2 +b2

Answer 1

$a+b=3 \sqrt{6} \\ \\ (a+b)^2=(3 \sqrt{6})^2 \\ \\ a^2+2ab+b^2=54 \\ \\ a^2+2 \cdot 16+b^2=54 \\ \\ a^2+32+b^2=54 \\ \\ a^2+b^2=54-32 \\ \\ \boxed{a^2+b^2=22}$

Answer 2

$a+b=3\sqrt{6} \\ (a+b)^{2}=(3\sqrt{6})^{2} \\ (a+b)(a+b)=\sqrt{3^{2}*6}}^{2} \\ aa+ab+ba+bb=\sqrt{9*6}}^{2} \\ a^{2}+2ab+b^{2}=\sqrt{54}^{2} \\ a^{2}+2*16+b^{2}=54 \\ a^{2}+32+b^{2}=54 \\ a^{2}+b^{2}=54-32 \\ a^{2}+b^{2}=22$