Question

(a+b)×(b+c)×(c+a)-(a+b)×(b-c)×(a+c) , efectuati factorul comun

Answer 1

comun ai (a+b) si (a+c)
deci avem:

(a+b)x(a+c)x[(b+c)-(b-c)]=(a+b)x(a+c)x(b+c-b+c)=(a+b)x(a+c)x2c=2x(a+b)x(a+c)

Answer 2

(a+b)(a+c)[b+c-(b-c)]=
=(a+b)(a+c)(b+c-b+c)
=2c(a+b)(a+c)