Question

a+b+c=153 a>b cu 10 c:(a+b)=3 rest 17 cum rezolvam?

Answer 1

a+b+c=153

b= a-10

c:(a+b)=3rest17 ⇒ c = 3·(a+b) + 17 ⇒ c=3a+3b+17 (inlocuim pe b=a-10) ⇒

c = 3a + 3(a-10)+17 ⇒ c=3a+3a-30+17

c=6a-13

a+b+c=153

a+a-10+6a-13=153

8a=153+23

8a=176

a=176:8

a=22

b=a-10

b=22-10

b=12

c=6a-13=6x22-13=132-13=119

c=119

proba:

a+b+c=22+12+119=153